Saturday, January 22, 2011

IMPORTANT FORMULA FOR CALENDER BASED PROBLEMS

  1. Odd Days:

    We are supposed to find the day of the week on a given date.

    For this, we use the concept of 'odd days'.

    In a given period, the number of days more than the complete weeks are called odd days.

  2. Leap Year:

    (i). Every year divisible by 4 is a leap year, if it is not a century.

    (ii). Every 4th century is a leap year and no other century is a leap year.

    Note: A leap year has 366 days.

    Examples:

    1. Each of the years 1948, 2004, 1676 etc. is a leap year.

    2. Each of the years 400, 800, 1200, 1600, 2000 etc. is a leap year.

    3. None of the years 2001, 2002, 2003, 2005, 1800, 2100 is a leap year.

  3. Ordinary Year:

    The year which is not a leap year is called an ordinary years. An ordinary year has 365 days.

  4. Counting of Odd Days:

    1. 1 ordinary year = 365 days = (52 weeks + 1 day.)

       1 ordinary year has 1 odd day.

    2. 1 leap year = 366 days = (52 weeks + 2 days)

       1 leap year has 2 odd days.

    3. 100 years = 76 ordinary years + 24 leap years

        = (76 x 1 + 24 x 2) odd days = 124 odd days.

        = (17 weeks + days)  5 odd days.

       Number of odd days in 100 years = 5.

      Number of odd days in 200 years = (5 x 2)  3 odd days.

      Number of odd days in 300 years = (5 x 3)  1 odd day.

      Number of odd days in 400 years = (5 x 4 + 1)  0 odd day.

      Similarly, each one of 800 years, 1200 years, 1600 years, 2000 years etc. has 0 odd days.

  5. Day of the Week Related to Odd Days:

    No. of days: 01 2 34 5 6
    Day: Sun.Mon. Tues.Wed. Thurs.Fri. Sat.

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